problem 31 solution

master
mitchellhansen 7 years ago
parent b3831fb360
commit 613b011d07

@ -1,45 +1,29 @@
# solving this recursively is an interesting solution # thank you http://algorithms.tutorialhorizon.com/dynamic-programming-coin-change-problem/
import itertools coin_list = [1, 2, 5, 10, 20, 50, 100, 200]
set_list = set()
permutation_list = list(itertools.combinations(list([1, 2, 5, 10, 20, 50, 100, 200]), 2))
success_count = 0 def coin(v, amount):
solution = [[0 for x in range(amount + 1)] for y in range(len(v) + 1)]
def recursive_coin_add(value, ciel): if amount == 0:
return 0
if value == ciel: for i in range(0, len(v) + 1):
global success_count solution[i][0] = 1
success_count += 1
return
if 1 + value <= ciel: for i in range (1, amount + 1):
recursive_coin_add(1 + value, ciel) solution[0][i] = 0
if 2 + value <= ciel: for i in range(1, len(v) + 1):
recursive_coin_add(2 + value, ciel) for j in range(1, amount + 1):
if v[i - 1] <= j:
solution[i][j] = solution[i - 1][j] + solution[i][j - v[i - 1]]
else:
solution[i][j] = solution[i - 1][j]
return solution[len(v)][amount]
if 5 + value <= ciel:
recursive_coin_add(5 + value, ciel)
if 10 + value <= ciel: print(coin(coin_list, 200))
recursive_coin_add(10 + value, ciel)
if 20 + value <= ciel:
recursive_coin_add(20 + value, ciel)
if 50 + value <= ciel:
recursive_coin_add(50 + value, ciel)
if 100 + value <= ciel:
recursive_coin_add(100 + value, ciel)
if 200 + value <= ciel:
recursive_coin_add(200 + value, ciel)
recursive_coin_add(0, 200)
print(success_count)
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